If a 1 2 −1 −1 1 2 2 −1 1 then adj adja
Web24 jan. 2024 · If the matrices A = [ (1, 1, 2), (1, 3, 4), (1, - 1, 3)], B = adjA and C = 3A, then adjB / c is equal to : (1) 72 (2) 2 (3) 8 (4) 16 jee main 2024 Share It On 2 Answers 0 votes answered Jan 24, 2024 by Sarita01 (54.2k points) selected Jan 28, 2024 by AmanYadav Best answer Answer is (3) 8 +1 vote answered Jan 25, 2024 by Beepin (59.2k points) WebThe value of the determinant. 6. If [sin2 αcos2 α cos2 αsin2 α] = 0,α ∈ (0,π), then the values of α are. 7. If α,β and γ are the roots of x3 + ax2 +b = 0, then the value of ∣∣α β γ β γ α γ …
If a 1 2 −1 −1 1 2 2 −1 1 then adj adja
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Webwhy create a profile on Shaalaa.com? 1. Inform you about time table of exam. 2. Inform you about new question papers. 3. New video tutorials information. WebSolution Verified by Toppr Step 1: Using the Inverse formula to prove the given relation. We know that A −1= ∣A∣adjA ∴A.adjA=∣A∣I...........(1) Substituting A with adjA adjA.adj(adjA)=∣adjA∣I From (1) adjA= A∣A∣I.............(2) Substituting (2) in (1) A∣A∣Iadj(adjA)=∣adjA∣I...............(3) Taking determinant on both sides of (1) ∣A.adjA∣=∣∣A∣I∣
Web30 mrt. 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. WebInverse Function. For any one-to-one function f(x) = y, a function f − 1(x) is an inverse function of f if f − 1(y) = x. This can also be written as f − 1(f(x)) = x for all x in the domain of f. It also follows that f(f − 1(x)) = x for all x in the domain of f − 1 if f − 1 is the inverse of f. The notation f − 1 is read “f ...
WebIf A = ⎡ ⎢ ⎣ 1 1 1 1 0 2 2 1 0 ⎤ ⎥ ⎦, I is the unit matrix of order 3 and a A 3 + b A 2 + c A – I = B, where B is null matrix of order 3 × 3, then Q. If ⎡ ⎢ ⎣ 1 3 0 1 0 − 2 − 4 − 4 4 ⎤ ⎥ ⎦ = A + B where A is symmetric matrix and B is skew-symmetric, then A − B is equal to WebIf a = ⎡ ⎢ ⎣ 1 2 − 1 − 1 1 2 2 − 1 1 ⎤ ⎥ ⎦ , Then Ded (Adj (Adj A)) is . CBSE Science (English Medium) Class 12. Question Papers 1879. Textbook Solutions 24705. MCQ Online Mock …
WebWBJEE 2010: If A = [1&2 -4&-1] then A-1 is (A) (1/7) [-1&-2 4&1] (B) (1/7) [1&2 -4&-1] (C) (1/7) [-1&2 4&-1] (D) Does not exist. Check Answer and Solu
Web24 sep. 2024 · If A = [(1, 2, 2) (2, 1, -2) (a, 2, b)] is a matrix satisfying the equation AA^T = 9I, where I is the identity matrix of order 3 asked Feb 14, 2024 in Matrices by … dbz kakarot all playable charactersWebUsing A−1, Solve the System of Linear Equations X − 2y = 10, 2x − Y − Z = 8, −2y + Z = 7 - Mathematics. Advertisement Remove all ads. Advertisement Remove all ads. If A = [ 1 2 … dbz kakarot community boardWeb8 okt. 2024 · If A = [ (1 2 2), (2 1 -2), (a 2 b)] is a matrix satisfying the equation AAT = 9I, where I is 3 x 3 identity matrix, then the ordered pair (a, b)is equal to. (a) (2, -1) (b) (-2, … dbz kakarot best community setupWebSolution Here, A = [ 1 2 0 − 2 − 1 − 2 0 − 1 1] A = 1 ( − 1 − 2) + 2 ( 2) = − 3 + 4 = 1 Let be the cofactors of the elements in Then, Let C i j be the cofactors of the elements a i j in A = [ a i j]. Then, C 11 = ( − 1) 1 + 1 − 1 − 2 − 1 1 = − 3, C 12 = ( − 1) 1 + 2 − 2 − 2 0 1 = 2, C 13 = ( − 1) 1 + 3 − 2 − 1 0 − 1 = 2 dbz kakarot cheat codes ps4WebIf A = ⎡⎢⎣12−1−1122−11⎤⎥⎦ then det Adj Adj A is 144 146 149 142 A =1+2−2−1−4−11−2=3+10+1=14∴det Adj Adj A= Adj A 2= A 4=144 Grade If A = … dbz kakarot best community board setupWeb30 mrt. 2024 · Transcript. Ex4.6, 15 If A = [ 8 (2&−3& 5@3 &2&− 4@1 &1&−2)], find A−1. Using A−1 solve the system of equations 2x – 3y + 5z = 11 3x + 2y – 4z = -5 x + y – 2z = -3 Writing equation as AX = B [ 8 (2&−3& 5@3 &2&− 4@1 &1&−2)] [ 8 (𝑥@𝑦@𝑧)] = [ 8 ( 11@ − 5@ −3)] Ex4.6, 15 If A = [ 8 (2&−3& 5@3 &2&− 4@1 &1&−2 ... dbz kakarot cheat codes xbox oneWeb28 mrt. 2024 · If A = [ (-1, -2, -2), (2, 1, -2), (2, -2, 1)], then adj A = ... (a) A (b) AT (c) 3A (d) 3AT matrices determinants jee jee mains 1 Answer +1 vote answered Mar 28, 2024 by … dbz kakarot big fish location