If x asectheta+btantheta
Webasecθ - btanθ = 5 ---- (i) atanθ - bsecθ = 3 ---- (ii) Formula used: sec 2 θ - tan 2 θ = 1 (a - b) 2 = a 2 + b 2 - 2ab Calculation: asecθ - btanθ = 5 ---- (i) atanθ - bsecθ = 3 ---- (ii) Squaring both side we get from (i), a 2 sec 2 θ + b 2 tan 2 θ - 2absecθtanθ = 25 ---- (iii) Squaring both side we get from (ii), Web4 nov. 2024 · Find the area of the ellipse x 2 + 9y 2 = 36 using integration. class-12; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered Nov 4, 2024 by Darshee (49.8k points) selected Nov 16, 2024 by Aanchi . Best answer. Required Area ← Prev ...
If x asectheta+btantheta
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Web21 feb. 2024 · If x=asec theta + btan theta and y = atan theta +bsec theta. prove that x square-y square=a square-b square - 2680061. yaseenkkk yaseenkkk 21.02.2024 Math … WebIf theta is a variable , find the equation to the locus of a moving point whose coordinates are (asectheta ,btantheta) Books. Physics. NCERT DC Pandey Sunil Batra HC Verma …
Webwhy create a profile on Shaalaa.com? 1. Inform you about time table of exam. 2. Inform you about new question papers. 3. New video tutorials information. Web8 nov. 2024 · 1answer. If x = a cos^3 θ and y = a sin^3 θ, then find the value of d^2y/dx^2 at θ = pi/6. askedNov 8, 2024in Mathematicsby Samantha(39.3kpoints) continuity and …
Web27 mrt. 2024 · The equation of normal becomes a h cos θ + b k cot θ = a 2 + b 2. Complete step-by-step answer: The normal of the Hyperbola is HK. The equation of normal at ( a sec θ, b tan θ) to the hyperbola x 2 a 2 − y 2 b 2 = 1 is a x cos θ + b y c o t θ = a 2 + b 2 . Therefore, normal at θ, Φ are a x cos θ + b y cot Φ = a 2 + b 2 Web30 mrt. 2024 · Ex 5.6, 9 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑𝑥, 𝑥=𝑎 sec 𝜃, 𝑦=𝑏 tan𝜃Here 𝑑𝑦/𝑑𝑥 = (𝑑𝑦/𝑑𝜃)/ (𝑑𝑥/𝑑𝜃) Calculating 𝒅𝒚/𝒅𝜽 𝑑𝑦/𝑑𝜃 = 𝑑 (𝑏 …
Web12 apr. 2024 · "Find `(dy)/(dx)`, if `x=asectheta`, `y=btantheta`"
Web17 aug. 2016 · Step-by-step explanation :- We have, x = a sec ∅ + b tan ∅ . y = a tan ∅ + b sec ∅ . °•° x² –y² . = (a sec ∅ + b tan ∅)² – (a tan ∅ + b sec ∅ )² . = ( a² sec²∅ + b²tan²∅ + … bve5 321 系ダウンロードWeb21 mrt. 2024 · The expression given to us is a sec θ − b tan θ ∀ θ ∈ ( 0, π 2) and we also know that a > b > 0. So, let f ( θ) = a sec θ − b tan θ. Now, to find the extreme values, we will derivate this f ( θ) once and equate it to 0. We know that derivative sec x is sec x tan x and tan x is sec 2 x. Thus f ′ ( θ) = a sec θ tan θ − b sec 2 θ bve5323系車両データWeb27 mrt. 2024 · Let \\[P\\left( {asec\\theta ,btan\\theta } \\right)\\] and \\[Q\\left( {asec\\phi ,btan\\phi } \\right),\\] where $\\theta + \\Phi = \\dfrac{\\pi }{2}$ , be two ... 富士フイルム irWebIf domain of f(x) is [-1, 2], then find the domain of f([x]-x^2+4), where [ ]denotes greatest... Answer & Earn Cool Goodies the diameter of a roller is 84 cm and its length is 120 cm. it … 富士フィルム biセミナーWebIf x= asecθ+btanθ x = a sec θ + b tan θ and y =atanθ+bsecθ y = a tan θ + b sec θ , prove that x2−y2 = a2 −b2 x 2 − y 2 = a 2 − b 2 Solution Given, x = asecθ+btanθ x = a sec θ + … 富士フイルム x-t30 動画WebLet P a sec θ , b tanθ and Q a sec φ , b tanφ , where θ + φ = π/2, be two points on the hyperbola x2/a2 y2/b2= 1. If h, k is the point of intersection of the normal at P and Q, … bve5 5050系4000番台 ダウンロードWebIf displaystyle x=asec theta +btan theta , y=atan theta +bsec theta , then bve5 381系 アーカイブ